DH930
Member
In this picture, would the assembly go like:
- install left bearing
- install pipe sleeve
- install right bearing
- install spindle driver part over this assembly
- is the sleeve an actual part or something you are wanting to adapt?
- does the end of sleeve rest on the inner bearing rings but basically slides on arbor shaft?
- what bearing number is the 'new' bearing you were referring to? 5/8" = 0.625" maybe? And that comes in 35mm OD?
- any chance you could go to a 17mm ID x 35mm OD bearing? Turning a ring with ~ .025" wall thickness (.620" ID x 0.669" OD x bearing width) is more do-able. Still a bit delicate but I think do-able.
- the brass shim stock kit I have is 0.001, 0.0015, 0.002, 0.003, 0.004...
So 0.002" would be likely thickness. It might work but it also might be a flaky solution.
The assembly order is as follow:
- install left bearing
- install pipe sleeve
- install spindle driver
- install right bearing
Q: is the sleeve an actual part or something you are wanting to adapt?
A: the sleeve is an actual part of the assembly and nothing is needed for this part. I was referring to if the spindle was to be replicated.
Q: does the end of sleeve rest on the inner bearing rings but basically slides on arbor shaft?
A: Yes, it does.
Q: what bearing number is the 'new' bearing you were referring to? 5/8" = 0.625" maybe? And that comes in 35mm OD?
A: The replacement bearing is 202SZZ3 with OD 35mm or 1.378", ID .625"
The bearings capped the driver so that the inner ring of the bearings fit tightly on the spindle while the outer ring of the bearings fit tightly on the driver's opening. The tail end of the driver has threaded opening and that is where you tighten up to hold the bearings/driver onto the spindle. There are other parts that attached to the tail end of the spindle where the pulley wheel integrate with the spindle and the drill head.