Are you sure the gear is dp and not metric?
How did you arrive at the 16 DP?
Another approximation is to use: DP=(N+2)/OD. From that it would appear that the gear you have has an OD of ~1” if the DP=16. Can you confirm that?
Perhaps they came with two sets of gears?
Huh, no idea. If I’m getting this right the existing arrangement presents a lower gear ratio resulting in a slower or smaller increment in the table movement? I don’t know why you would need that unless to lessen the chances of burying a cutter during a cut. I confess I don’t use the vertical feed on my machine, only the horizontal, but I can see if you’re trying to sneak up on something like a keyway depth it’s real easy to have that relatively wide cutting edge grab and bury itself. A smaller increment might make that less likely.can you comment on this?
Since this will be a low speed, low torque application, even if the PAs were different, it should still be fine.
If you can’t find a suitable gear online, I can make you a 28T, 16DP, 14.5*PA gear; I just checked, I have the correct involute cutter.
I have a gear pitch gage. It is for 14.5* PA. The cutters are labelled with ”14.5* PA”. We could check the little 14T gear you have.